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Roots of Equations In More Than One Variable

Posted by Beetle B. on Thu 28 October 2021
2x2xy+y2=4
4x25xy+3y2=6

Manipulate the two equations so that there is no constant term, and then factorize to get (2xy)(x3y)=0.

solve([x^3==1], x)
[x == 1/2*I*sqrt(3) - 1/2, x == -1/2*I*sqrt(3) - 1/2, x == 1]