2∗x2−xy+y2=4
4∗x2−5xy+3y2=6
Manipulate the two equations so that there is no constant term, and then factorize to get (2x−y)(x−3y)=0.
solve([x^3==1], x)
[x == 1/2*I*sqrt(3) - 1/2, x == -1/2*I*sqrt(3) - 1/2, x == 1]
Manipulate the two equations so that there is no constant term, and then factorize to get (2x−y)(x−3y)=0.
solve([x^3==1], x)
[x == 1/2*I*sqrt(3) - 1/2, x == -1/2*I*sqrt(3) - 1/2, x == 1]