For a Poission distribution with large \(n\), use \(Z=\frac{\bar{X}-\lambda}{\sqrt{\lambda/n}}\) (i.e. \(\lambda\) instead of \(S\)).
It is approximately normal. Use it to test \(H_{0}:\lambda=\lambda_{0}\)
For a Poission distribution with large \(n\), use \(Z=\frac{\bar{X}-\lambda}{\sqrt{\lambda/n}}\) (i.e. \(\lambda\) instead of \(S\)).
It is approximately normal. Use it to test \(H_{0}:\lambda=\lambda_{0}\)